What is the answer to log_{10}(x)+log_{10}(x+2)=1 ?

The answer to log_{10}(x)+log_{10}(x+2)=1 is x=-1+sqrt(11)

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log_{10}(x)+log_{10}(x+2)=1

lo g_{10} (x) + lo g_{10} (x + 2) = 1

x = - 1 + 11

Decimal

x = 2.31662 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 2) = 1

Apply log rules

x (x + 2) = 10

Solve

x (x + 2) = 10 : x = - 1 + 11, x = - 1 - 11

x = - 1 + 11, x = - 1 - 11

Verify Solutions:

x = - 1 + 11

True

, x = - 1 - 11

False

The solution is

x = - 1 + 11

lo g_{2} (10 + 3 x) = 5

lo g_{2} (1 + x) = 6

y, ln (y) = x

lo g_{3} (x^{2} + 2) = 3

lo g_{10} (4 x) + lo g_{10} (2) = lo g_{10} (48)

What is the answer to log_{10}(x)+log_{10}(x+2)=1 ?
The answer to log_{10}(x)+log_{10}(x+2)=1 is x=-1+sqrt(11)
Solve for x: log_{10}(x)+log_{10}(x+2)=1
The solution is x=-1+sqrt(11)