What is the answer to 4ln(x^2)-7ln(x)+ln(x+3)=0 ?

The answer to 4ln(x^2)-7ln(x)+ln(x+3)=0 is x=(-3+sqrt(13))/2

Solve for x: 4ln(x^2)-7ln(x)+ln(x+3)=0

The solution is x=(-3+sqrt(13))/2

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4 ln (x^{2}) - 7 ln (x) + ln (x + 3) = 0

x = \frac{- 3 + 13}{2}

Decimal

x = 0.30277 \dots

Solution steps

4 ln (x^{2}) - 7 ln (x) + ln (x + 3) = 0

Apply log rules

x^{8} (x + 3) = x^{7}

Solve

x^{8} (x + 3) = x^{7} : x = 0, x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

x = 0, x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

Verify Solutions:

x = 0

False

, x = \frac{- 3 + 13}{2}

True

, x = \frac{- 3 - 13}{2}

False

The solution is

x = \frac{- 3 + 13}{2}

6 ln (x) - 3 = 2 - ln (x)

lo g_{8} (28 k - 20) + 15 = 18

2 ln (x) = ln (2) + ln (x + 4)

lo g_{5} (x + 10) = 2

\frac{- 2 ln ( x ) + 1}{x ^{3}} = 0

What is the answer to 4ln(x^2)-7ln(x)+ln(x+3)=0 ?
The answer to 4ln(x^2)-7ln(x)+ln(x+3)=0 is x=(-3+sqrt(13))/2
Solve for x: 4ln(x^2)-7ln(x)+ln(x+3)=0
The solution is x=(-3+sqrt(13))/2