What are the solutions to the equation 5x^2=13x+6 ?

The solutions to the equation 5x^2=13x+6 are x=3,x=-2/5

Find the zeros of 5x^2=13x+6

The zeros of 5x^2=13x+6 are x=3,x=-2/5

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5 x^{2} = 13 x + 6

x = 3, x = - \frac{2}{5}

Decimal Notation

x = 3, x = - 0.4

Solution steps

5 x^{2} = 13 x + 6

Move

6

to the left side

5 x^{2} - 6 = 13 x

Move

13 x

to the left side

5 x^{2} - 6 - 13 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 13 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 13)^{2} - 4 \cdot 5 (- 6) = 17

x_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 5}, x_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 5}

x = \frac{- ( - 13 ) + 17}{2 \cdot 5} : 3

x = \frac{- ( - 13 ) - 17}{2 \cdot 5} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = 3, x = - \frac{2}{5}

- 9 x (10 - 2 x) = - 3 x^{2}

\frac{1}{6} x + \frac{2}{3} = \frac{1}{4} x - \frac{1}{3}

\frac{3}{4} + \frac{1}{16}

\frac{x}{3} = 0

(2 x + 3)^{2} = 49

What are the solutions to the equation 5x^2=13x+6 ?
The solutions to the equation 5x^2=13x+6 are x=3,x=-2/5
Find the zeros of 5x^2=13x+6
The zeros of 5x^2=13x+6 are x=3,x=-2/5