What is the answer to (\sqrt[4]{7w-5})/2 =\sqrt[4]{w-2} ?

The answer to (\sqrt[4]{7w-5})/2 =\sqrt[4]{w-2} is w=3

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(\sqrt[4]{7w-5})/2 =\sqrt[4]{w-2}

\frac{4 7 w - 5}{2} = 4 w - 2

w = 3

Solution steps

\frac{4 7 w - 5}{2} = 4 w - 2

Multiply both sides by

2

\frac{4 7 w - 5}{2} \cdot 2 = 4 w - 2 \cdot 2

Simplify

4 7 w - 5 = 4 w - 2 \cdot 2

Take both sides of the equation to the power of

4 : 7 w - 5 = 16 w - 32

7 w - 5 = 16 w - 32

Solve

7 w - 5 = 16 w - 32 : w = 3

w = 3

Verify Solutions:

w = 3

True

The solution is

w = 3

3 3 x - 4 = 3 x - 3

x - 2 x + 3 = 6

x + 1 + 2 x = 5 x + 3

4 x - 3 - x + 1 = 1

x^{2} + 2 x + 9 - 7 = 2 x

What is the answer to (\sqrt[4]{7w-5})/2 =\sqrt[4]{w-2} ?
The answer to (\sqrt[4]{7w-5})/2 =\sqrt[4]{w-2} is w=3
Solve for w: (\sqrt[4]{7w-5})/2 =\sqrt[4]{w-2}
The solution is w=3