What is the answer to x^2-4x=3sqrt(x^2-4x+20)-10 ?

The answer to x^2-4x=3sqrt(x^2-4x+20)-10 is x=-1,x=5

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x^2-4x=3sqrt(x^2-4x+20)-10

x^{2} - 4 x = 3 x^{2} - 4 x + 20 - 10

x = - 1, x = 5

Solution steps

x^{2} - 4 x = 3 x^{2} - 4 x + 20 - 10

Remove square roots

x^{4} - 8 x^{3} + 36 x^{2} - 80 x + 100 = 9 x^{2} - 36 x + 180

Solve

x^{4} - 8 x^{3} + 36 x^{2} - 80 x + 100 = 9 x^{2} - 36 x + 180 : x = - 1, x = 5

x = - 1, x = 5

Verify Solutions:

x = - 1

True

, x = 5

True

The solutions are

x = - 1, x = 5

2 x - 36 - 2 x = 6

x + 7 - x = 1

x + x - 8 = 12

9 + x - 5 = \frac{2 x + 1}{3}

x + 5 = 12

What is the answer to x^2-4x=3sqrt(x^2-4x+20)-10 ?
The answer to x^2-4x=3sqrt(x^2-4x+20)-10 is x=-1,x=5
Solve for x: x^2-4x=3sqrt(x^2-4x+20)-10
The solution is x=-1,x=5