What is the answer to cube root of x-1}=\sqrt{x-1 ?

The answer to cube root of x-1}=\sqrt{x-1 is x=1,x=2

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cube root of x-1}=\sqrt{x-1

3 x - 1 = x - 1

x = 1, x = 2

Solution steps

3 x - 1 = x - 1

Take both sides of the equation to the power of

6 : (x - 1)^{2} = (x - 1)^{3}

(x - 1)^{2} = (x - 1)^{3}

Solve

(x - 1)^{2} = (x - 1)^{3} : x = 1, x = 2

x = 1, x = 2

Verify Solutions:

x = 1

True

, x = 2

True

The solutions are

x = 1, x = 2

3 3 2 x - 1 = 27

6 x^{0.5} - 24 x^{- \frac{3}{2}} = 0

8 x = 32

2 x - 1 + x + 4 = 6

x^{\frac{3}{5}} + 1 = 0

What is the answer to cube root of x-1}=\sqrt{x-1 ?
The answer to cube root of x-1}=\sqrt{x-1 is x=1,x=2
Solve for x: cube root of x-1}=\sqrt{x-1
The solution is x=1,x=2