What are the solutions to the equation -2x(-x^2+12)=0 ?

The solutions to the equation -2x(-x^2+12)=0 are x=0,x=-2sqrt(3),x=2sqrt(3)

Find the zeros of -2x(-x^2+12)=0

The zeros of -2x(-x^2+12)=0 are x=0,x=-2sqrt(3),x=2sqrt(3)

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- 2 x (- x^{2} + 12) = 0

x = 0, x = - 23, x = 23

Decimal

x = 0, x = - 3.46410 \dots, x = 3.46410 \dots

Solution steps

- 2 x (- x^{2} + 12) = 0

Factor

- 2 x (- x^{2} + 12) : 2 x (x + 23) (x - 23)

2 x (x + 23) (x - 23) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 23 = 0 or x - 23 = 0

Solve

x + 23 = 0 : x = - 23

Solve

x - 23 = 0 : x = 23

The solutions are

x = 0, x = - 23, x = 23

5 x + 21 = 10 x^{19}

x^{4} - 2 x^{3} - 8 x^{2} + 18 x - 9 = 0

7 x^{3} - 35 x^{2} - 252 x = 0

y^{3} = 64 y

2 = y^{3} + 2 y - 1

What are the solutions to the equation -2x(-x^2+12)=0 ?
The solutions to the equation -2x(-x^2+12)=0 are x=0,x=-2sqrt(3),x=2sqrt(3)
Find the zeros of -2x(-x^2+12)=0
The zeros of -2x(-x^2+12)=0 are x=0,x=-2sqrt(3),x=2sqrt(3)