What are the solutions to the equation roots x^3+2x^2+4x+8 ?

The solutions to the equation roots x^3+2x^2+4x+8 are x=-2,x=2i,x=-2i

Find the zeros of roots x^3+2x^2+4x+8

The zeros of roots x^3+2x^2+4x+8 are x=-2,x=2i,x=-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{3} + 2 x^{2} + 4 x + 8

x = - 2, x = 2 i, x = - 2 i

Solution steps

x^{3} + 2 x^{2} + 4 x + 8

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 2 x^{2} + 4 x + 8 = 0

Factor

x^{3} + 2 x^{2} + 4 x + 8 : (x + 2) (x^{2} + 4)

(x + 2) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - 2, x = 2 i, x = - 2 i

c^{3} + 2 c = 3

x^{3} + x^{2} - 2 = 0

4 x^{4} - 36 x^{2} = 0

(x - 1) (x^{2} + 1) = 0

x^{4} + 4 x + 3 = 0

What are the solutions to the equation roots x^3+2x^2+4x+8 ?
The solutions to the equation roots x^3+2x^2+4x+8 are x=-2,x=2i,x=-2i
Find the zeros of roots x^3+2x^2+4x+8
The zeros of roots x^3+2x^2+4x+8 are x=-2,x=2i,x=-2i