What are the solutions to the equation x^3+8x^2+5x-14=0 ?

The solutions to the equation x^3+8x^2+5x-14=0 are x=1,x=-2,x=-7

Find the zeros of x^3+8x^2+5x-14=0

The zeros of x^3+8x^2+5x-14=0 are x=1,x=-2,x=-7

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x^{3} + 8 x^{2} + 5 x - 14 = 0

x = 1, x = - 2, x = - 7

Solution steps

x^{3} + 8 x^{2} + 5 x - 14 = 0

Factor

x^{3} + 8 x^{2} + 5 x - 14 : (x - 1) (x + 2) (x + 7)

(x - 1) (x + 2) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x + 7 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x + 7 = 0 : x = - 7

The solutions are

x = 1, x = - 2, x = - 7

4 x^{3} + 12 x^{2} - 4 x = 0

x^{6} - 14 x^{4} + 3 x^{2} - 42 = 0

x, 2 = x^{4} + x^{2}

x^{4} - x^{3} - 13 x^{2} + x + 12 = 0

s^{3} + 10.6 s^{2} + 7 s + 10 = 0

What are the solutions to the equation x^3+8x^2+5x-14=0 ?
The solutions to the equation x^3+8x^2+5x-14=0 are x=1,x=-2,x=-7
Find the zeros of x^3+8x^2+5x-14=0
The zeros of x^3+8x^2+5x-14=0 are x=1,x=-2,x=-7