What are the solutions to the equation (r^2+6r+13)^2=0 ?

The solutions to the equation (r^2+6r+13)^2=0 are r=-3+2i,r=-3-2i

Find the zeros of (r^2+6r+13)^2=0

The zeros of (r^2+6r+13)^2=0 are r=-3+2i,r=-3-2i

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(r^{2} + 6 r + 13)^{2} = 0

r = - 3 + 2 i, r = - 3 - 2 i

Solution steps

(r^{2} + 6 r + 13)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

r^{2} + 6 r + 13 = 0 : r = - 3 + 2 i, r = - 3 - 2 i

The solutions are

r = - 3 + 2 i, r = - 3 - 2 i

2 x^{4} - 3 x^{3} = 9 x^{2}

6 x^{3} + x^{2} - 54 x - 9 = 0

x^{4} - 11 x^{2} - 12 x + 4 = 0

(x - 1) (x^{2} + 6 x + 9) = 5 (x + 3)

x^{3} - 5 x^{2} + 25 x - 125 = 0

What are the solutions to the equation (r^2+6r+13)^2=0 ?
The solutions to the equation (r^2+6r+13)^2=0 are r=-3+2i,r=-3-2i
Find the zeros of (r^2+6r+13)^2=0
The zeros of (r^2+6r+13)^2=0 are r=-3+2i,r=-3-2i