What are the solutions to the equation 8x^3-46x^2+31x-5=0 ?

The solutions to the equation 8x^3-46x^2+31x-5=0 are x=5,x= 1/4 ,x= 1/2

Find the zeros of 8x^3-46x^2+31x-5=0

The zeros of 8x^3-46x^2+31x-5=0 are x=5,x= 1/4 ,x= 1/2

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8 x^{3} - 46 x^{2} + 31 x - 5 = 0

x = 5, x = \frac{1}{4}, x = \frac{1}{2}

Decimal

x = 5, x = 0.25, x = 0.5

Solution steps

8 x^{3} - 46 x^{2} + 31 x - 5 = 0

Factor

8 x^{3} - 46 x^{2} + 31 x - 5 : (x - 5) (4 x - 1) (2 x - 1)

(x - 5) (4 x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or 4 x - 1 = 0 or 2 x - 1 = 0

Solve

x - 5 = 0 : x = 5

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 5, x = \frac{1}{4}, x = \frac{1}{2}

(x - 2)^{4} - (x - 2)^{2} - 6 = 0

5 x^{3} + 5 x^{2} - 4 x - 4

n^{3} - n = 3 n^{2} - 3

x^{5} + 4 + 4 i = 0

4 x^{4} + 15 x^{2} - 4 = 0

What are the solutions to the equation 8x^3-46x^2+31x-5=0 ?
The solutions to the equation 8x^3-46x^2+31x-5=0 are x=5,x= 1/4 ,x= 1/2
Find the zeros of 8x^3-46x^2+31x-5=0
The zeros of 8x^3-46x^2+31x-5=0 are x=5,x= 1/4 ,x= 1/2