What are the solutions to the equation factor 4x^3-8x^2-25x+50=0 ?

The solutions to the equation factor 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2

Find the zeros of factor 4x^3-8x^2-25x+50=0

The zeros of factor 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2

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factor

4 x^{3} - 8 x^{2} - 25 x + 50 = 0

x = 2, x = - \frac{5}{2}, x = \frac{5}{2}

Decimal

x = 2, x = - 2.5, x = 2.5

Solution steps

4 x^{3} - 8 x^{2} - 25 x + 50 = 0

Factor

4 x^{3} - 8 x^{2} - 25 x + 50 : (x - 2) (2 x + 5) (2 x - 5)

(x - 2) (2 x + 5) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 5 = 0 or 2 x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions are

x = 2, x = - \frac{5}{2}, x = \frac{5}{2}

4 x^{3} + 12 x^{2} + 9 x = 0

y, 9 x^{5} + 6 y^{3} = 5 x + 10 x^{6}

x^{4} + 6 x^{3} - 5 x^{2} - 24 x + 4 = 0

x^{4} + 6 x^{3} + 8 x^{2} - 6 x - 9 = 0

x^{4} - 9 x^{3} + 27 x^{2} - 27 x = 0

What are the solutions to the equation factor 4x^3-8x^2-25x+50=0 ?
The solutions to the equation factor 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2
Find the zeros of factor 4x^3-8x^2-25x+50=0
The zeros of factor 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2