What are the solutions to the equation x^4-3x^2+2x=0 ?

The solutions to the equation x^4-3x^2+2x=0 are x=0,x=1,x=-2

Find the zeros of x^4-3x^2+2x=0

The zeros of x^4-3x^2+2x=0 are x=0,x=1,x=-2

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x^{4} - 3 x^{2} + 2 x = 0

x = 0, x = 1, x = - 2

Solution steps

x^{4} - 3 x^{2} + 2 x = 0

Factor

x^{4} - 3 x^{2} + 2 x : x (x - 1)^{2} (x + 2)

x (x - 1)^{2} (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 0, x = 1, x = - 2

x^{3} - 7 x^{2} + 5 x + 25 = 0

x^{3} + 5 x^{2} + 4 x + 20

x, x^{3} = a t^{2}

12 x^{3} - 20 x^{2} + x + 3

3 x^{4} + 5 x^{3} - 12 x^{2} - 20 x = 0

What are the solutions to the equation x^4-3x^2+2x=0 ?
The solutions to the equation x^4-3x^2+2x=0 are x=0,x=1,x=-2
Find the zeros of x^4-3x^2+2x=0
The zeros of x^4-3x^2+2x=0 are x=0,x=1,x=-2