-3x^2+2x+7=0

Lösung

- 3 x^{2} + 2 x + 7 = 0

x = - \frac{- 1 + 22}{3}, x = \frac{1 + 22}{3}

Dezimale

x = - 1.23013 \dots, x = 1.89680 \dots

Schritte zur Lösung

- 3 x^{2} + 2 x + 7 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 7}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 7 = 222

x_{1, 2} = \frac{- 2 \pm 2 22}{2 ( - 3 )}

Trenne die Lösungen

x_{1} = \frac{- 2 + 2 22}{2 ( - 3 )}, x_{2} = \frac{- 2 - 2 22}{2 ( - 3 )}

x = \frac{- 2 + 2 22}{2 ( - 3 )} : - \frac{- 1 + 22}{3}

x = \frac{- 2 - 2 22}{2 ( - 3 )} : \frac{1 + 22}{3}

Die Lösungen für die quadratische Gleichung sind:

x = - \frac{- 1 + 22}{3}, x = \frac{1 + 22}{3}

5 z^{2} - 20 z + 25 = z^{2}

4 x^{2} - 12 x + 9 = 36

- 5 v^{2} + 9 v + 1 = - 6 v^{2}

d^{2} + 10 d + 28 = 3

f a c t or x^{2} + 61 = 1 - 17 x