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Frequently Asked Questions (FAQ)
What are the solutions to the equation 5(3x-2)^2+27=32 ?
- The solutions to the equation 5(3x-2)^2+27=32 are x=1,x= 1/3
Find the zeros of 5(3x-2)^2+27=32
- The zeros of 5(3x-2)^2+27=32 are x=1,x= 1/3