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Frequently Asked Questions (FAQ)
What are the solutions to the equation -k^2-3k-2=-5k^2 ?
- The solutions to the equation -k^2-3k-2=-5k^2 are k=(3+sqrt(41))/8 ,k=(3-sqrt(41))/8
Find the zeros of -k^2-3k-2=-5k^2
- The zeros of -k^2-3k-2=-5k^2 are k=(3+sqrt(41))/8 ,k=(3-sqrt(41))/8