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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3(4x+3)^2+1=16 ?
- The solutions to the equation 3(4x+3)^2+1=16 are x=(sqrt(5)-3)/4 ,x=(-sqrt(5)-3)/4
Find the zeros of 3(4x+3)^2+1=16
- The zeros of 3(4x+3)^2+1=16 are x=(sqrt(5)-3)/4 ,x=(-sqrt(5)-3)/4