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受欢迎的代数 >

10x^2-148x+490=0

解答

10 x^{2} - 148 x + 490 = 0

解答

x = \frac{49}{5}, x = 5

+1

十进制

x = 9.8, x = 5

求解步骤

10 x^{2} - 148 x + 490 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 148 ) \pm ( - 148 ) ^{2} - 4 \cdot 10 \cdot 490}{2 \cdot 10}

(- 148)^{2} - 4 \cdot 10 \cdot 490 = 48

x_{1, 2} = \frac{- ( - 148 ) \pm 48}{2 \cdot 10}

将解分隔开

x_{1} = \frac{- ( - 148 ) + 48}{2 \cdot 10}, x_{2} = \frac{- ( - 148 ) - 48}{2 \cdot 10}

x = \frac{- ( - 148 ) + 48}{2 \cdot 10} : \frac{49}{5}

x = \frac{- ( - 148 ) - 48}{2 \cdot 10} : 5

二次方程组的解是:

x = \frac{49}{5}, x = 5

作图

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