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Frequently Asked Questions (FAQ)
What are the solutions to the equation 20^2=x^2+(x-4)^2 ?
- The solutions to the equation 20^2=x^2+(x-4)^2 are x=16,x=-12
Find the zeros of 20^2=x^2+(x-4)^2
- The zeros of 20^2=x^2+(x-4)^2 are x=16,x=-12