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受欢迎的代数 >

2q^2+6q-7=0

解答

2 q^{2} + 6 q - 7 = 0

解答

q = \frac{- 3 + 23}{2}, q = - \frac{3 + 23}{2}

+1

十进制

q = 0.89791 \dots, q = - 3.89791 \dots

求解步骤

2 q^{2} + 6 q - 7 = 0

使用求根公式求解

q_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 7) = 223

q_{1, 2} = \frac{- 6 \pm 2 23}{2 \cdot 2}

将解分隔开

q_{1} = \frac{- 6 + 2 23}{2 \cdot 2}, q_{2} = \frac{- 6 - 2 23}{2 \cdot 2}

q = \frac{- 6 + 2 23}{2 \cdot 2} : \frac{- 3 + 23}{2}

q = \frac{- 6 - 2 23}{2 \cdot 2} : - \frac{3 + 23}{2}

二次方程组的解是:

q = \frac{- 3 + 23}{2}, q = - \frac{3 + 23}{2}

作图

流行的例子

2(4x+3)^2-46=-12

2 (4 x + 3)^{2} - 46 = - 12

solvefor y,x^2-2xy+3y^2=4

so l v e f or y, x^{2} - 2 x y + 3 y^{2} = 4

h^{2} - 3 h - 28 = 0

(x+5)^2+(x+3)^2=(2x+4)^2

(x + 5)^{2} + (x + 3)^{2} = (2 x + 4)^{2}

4 x^{2} + 19 x + 12 = - 5