What are the solutions to the equation 2x^2+2=5x ?

The solutions to the equation 2x^2+2=5x are x=2,x= 1/2

Find the zeros of 2x^2+2=5x

The zeros of 2x^2+2=5x are x=2,x= 1/2

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2 x^{2} + 2 = 5 x

x = 2, x = \frac{1}{2}

Decimal Notation

x = 2, x = 0.5

Solution steps

2 x^{2} + 2 = 5 x

Move

5 x

to the left side

2 x^{2} + 2 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 2 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 2}

x = \frac{- ( - 5 ) + 3}{2 \cdot 2} : 2

x = \frac{- ( - 5 ) - 3}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{2}

\frac{2 b}{b}

x^{2} - 4 x - 20 = 0

r^{2} + r = 0

6 k^{2} - 42 k + 72 = 0

36 x^{2} - 121

What are the solutions to the equation 2x^2+2=5x ?
The solutions to the equation 2x^2+2=5x are x=2,x= 1/2
Find the zeros of 2x^2+2=5x
The zeros of 2x^2+2=5x are x=2,x= 1/2