What are the solutions to the equation 8x^2-4x=0 ?

The solutions to the equation 8x^2-4x=0 are x= 1/2 ,x=0

Find the zeros of 8x^2-4x=0

The zeros of 8x^2-4x=0 are x= 1/2 ,x=0

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8 x^{2} - 4 x = 0

x = \frac{1}{2}, x = 0

Decimal Notation

x = 0.5, x = 0

Solution steps

8 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 4)^{2} - 4 \cdot 8 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 8}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 8}

x = \frac{- ( - 4 ) + 4}{2 \cdot 8} : \frac{1}{2}

x = \frac{- ( - 4 ) - 4}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

22 - 2

∣ - 3 x + 4 ∣ = 2 x + 6

5 x + 100 < 20

\frac{x}{6} = - 6

4. 2^{2}

What are the solutions to the equation 8x^2-4x=0 ?
The solutions to the equation 8x^2-4x=0 are x= 1/2 ,x=0
Find the zeros of 8x^2-4x=0
The zeros of 8x^2-4x=0 are x= 1/2 ,x=0