What are the solutions to the equation 300x^2+9x-(0.35*9)=0 ?

The solutions to the equation 300x^2+9x-(0.35*9)=0 are x=(-3+sqrt(429))/(200),x=-(3+sqrt(429))/(200)

Find the zeros of 300x^2+9x-(0.35*9)=0

The zeros of 300x^2+9x-(0.35*9)=0 are x=(-3+sqrt(429))/(200),x=-(3+sqrt(429))/(200)

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300 x^{2} + 9 x - (0.35 \cdot 9) = 0

x = \frac{- 3 + 429}{200}, x = - \frac{3 + 429}{200}

Decimal Notation

x = 0.08856 \dots, x = - 0.11856 \dots

Solution steps

300 x^{2} + 9 x - (0.35 \cdot 9) = 0

Expand

300 x^{2} + 9 x - (0.35 \cdot 9) : 300 x^{2} + 9 x - 3.15

300 x^{2} + 9 x - 3.15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 300 ( - 3.15 )}{2 \cdot 300}

9^{2} - 4 \cdot 300 (- 3.15) = 3429

x_{1, 2} = \frac{- 9 \pm 3 429}{2 \cdot 300}

Separate the solutions

x_{1} = \frac{- 9 + 3 429}{2 \cdot 300}, x_{2} = \frac{- 9 - 3 429}{2 \cdot 300}

x = \frac{- 9 + 3 429}{2 \cdot 300} : \frac{- 3 + 429}{200}

x = \frac{- 9 - 3 429}{2 \cdot 300} : - \frac{3 + 429}{200}

The solutions to the quadratic equation are:

x = \frac{- 3 + 429}{200}, x = - \frac{3 + 429}{200}

- \frac{x}{3} = 9

3^{5} \cdot 3^{3}

(6 x^{4} y)^{3}

64 \cdot 8

21 - 6 x = 27 - 8 x

What are the solutions to the equation 300x^2+9x-(0.35*9)=0 ?
The solutions to the equation 300x^2+9x-(0.35*9)=0 are x=(-3+sqrt(429))/(200),x=-(3+sqrt(429))/(200)
Find the zeros of 300x^2+9x-(0.35*9)=0
The zeros of 300x^2+9x-(0.35*9)=0 are x=(-3+sqrt(429))/(200),x=-(3+sqrt(429))/(200)