What are the solutions to the equation 11s^2-26s-61=0 ?

The solutions to the equation 11s^2-26s-61=0 are s=(13+2sqrt(210))/(11),s=(13-2sqrt(210))/(11)

Find the zeros of 11s^2-26s-61=0

The zeros of 11s^2-26s-61=0 are s=(13+2sqrt(210))/(11),s=(13-2sqrt(210))/(11)

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11 s^{2} - 26 s - 61 = 0

s = \frac{13 + 2 210}{11}, s = \frac{13 - 2 210}{11}

Decimal Notation

s = 3.81661 \dots, s = - 1.45297 \dots

Solution steps

11 s^{2} - 26 s - 61 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 11 ( - 61 )}{2 \cdot 11}

(- 26)^{2} - 4 \cdot 11 (- 61) = 4210

s_{1, 2} = \frac{- ( - 26 ) \pm 4 210}{2 \cdot 11}

Separate the solutions

s_{1} = \frac{- ( - 26 ) + 4 210}{2 \cdot 11}, s_{2} = \frac{- ( - 26 ) - 4 210}{2 \cdot 11}

s = \frac{- ( - 26 ) + 4 210}{2 \cdot 11} : \frac{13 + 2 210}{11}

s = \frac{- ( - 26 ) - 4 210}{2 \cdot 11} : \frac{13 - 2 210}{11}

The solutions to the quadratic equation are:

s = \frac{13 + 2 210}{11}, s = \frac{13 - 2 210}{11}

x^{2} + 16 x + 49 = 0

9 + x^{2} - 6

2 x^{2} - 3 \geq 5 x

310 \cdot 28

7 - 2 k \leq 3

What are the solutions to the equation 11s^2-26s-61=0 ?
The solutions to the equation 11s^2-26s-61=0 are s=(13+2sqrt(210))/(11),s=(13-2sqrt(210))/(11)
Find the zeros of 11s^2-26s-61=0
The zeros of 11s^2-26s-61=0 are s=(13+2sqrt(210))/(11),s=(13-2sqrt(210))/(11)