What are the solutions to the equation 2x(x-2)=7x^2-6x ?

The solutions to the equation 2x(x-2)=7x^2-6x are x=0,x= 2/5

Find the zeros of 2x(x-2)=7x^2-6x

The zeros of 2x(x-2)=7x^2-6x are x=0,x= 2/5

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2 x (x - 2) = 7 x^{2} - 6 x

x = 0, x = \frac{2}{5}

Decimal Notation

x = 0, x = 0.4

Solution steps

2 x (x - 2) = 7 x^{2} - 6 x

Expand

2 x (x - 2) : 2 x^{2} - 4 x

2 x^{2} - 4 x = 7 x^{2} - 6 x

Move

6 x

to the left side

2 x^{2} + 2 x = 7 x^{2}

Move

7 x^{2}

to the left side

- 5 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

2^{2} - 4 (- 5) \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 ( - 5 )}, x_{2} = \frac{- 2 - 2}{2 ( - 5 )}

x = \frac{- 2 + 2}{2 ( - 5 )} : 0

x = \frac{- 2 - 2}{2 ( - 5 )} : \frac{2}{5}

The solutions to the quadratic equation are:

x = 0, x = \frac{2}{5}

- x^{2} + 3 x + 4 = 0

\frac{1}{2} \cdot 90

2^{\frac{1}{2}} \cdot 2^{3}

(2 i - 1)^{2} (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

\frac{- 1 + 2 i}{- 1 - 2 i}

What are the solutions to the equation 2x(x-2)=7x^2-6x ?
The solutions to the equation 2x(x-2)=7x^2-6x are x=0,x= 2/5
Find the zeros of 2x(x-2)=7x^2-6x
The zeros of 2x(x-2)=7x^2-6x are x=0,x= 2/5