solvefor m,y=(x-3)^2minimo

解

解く

m, y = (x - 3)^{2} minim o

m = \frac{y}{o n ( x - 3 )} i, m = - \frac{y}{o n ( x - 3 )} i, m = \frac{y}{o n ( - x ^{2} + 6 x - 9 )}, m = - \frac{y}{o n ( - x ^{2} + 6 x - 9 )}

解答ステップ

y = (x - 3)^{2} minim o

代用

m = a + bi

y = (x - 3)^{2} (a + bi) ini (a + bi) o

拡張

(x - 3)^{2} (a + bi) ini (a + bi) o : (- n x^{2} o a^{2} + n x^{2} o b^{2} + 6 n x o a^{2} - 6 n x o b^{2} - 9 n o a^{2} + 9 n o b^{2}) + i (- 18 n o ab + 12 n x o ab - 2 n x^{2} o ab)

y = (- n x^{2} o a^{2} + n x^{2} o b^{2} + 6 n x o a^{2} - 6 n x o b^{2} - 9 n o a^{2} + 9 n o b^{2}) + i (- 18 n o ab + 12 n x o ab - 2 n x^{2} o ab)

標準的な複素数形式で

y

を書き換える:

y + 0 i

y + 0 i = (- n x^{2} o a^{2} + n x^{2} o b^{2} + 6 n x o a^{2} - 6 n x o b^{2} - 9 n o a^{2} + 9 n o b^{2}) + i (- 18 n o ab + 12 n x o ab - 2 n x^{2} o ab)

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[y = - n x^{2} o a^{2} + n x^{2} o b^{2} + 6 n x o a^{2} - 6 n x o b^{2} - 9 n o a^{2} + 9 n o b^{2} 0 = - 18 n o ab + 12 n x o ab - 2 n x^{2} o ab]

[y = - n x^{2} o a^{2} + n x^{2} o b^{2} + 6 n x o a^{2} - 6 n x o b^{2} - 9 n o a^{2} + 9 n o b^{2} 0 = - 18 n o ab + 12 n x o ab - 2 n x^{2} o ab] : a = 0, a = 0, a = \frac{y}{o n ( - x ^{2} + 6 x - 9 )}, a = - \frac{y}{o n ( - x ^{2} + 6 x - 9 )}, b = \frac{y}{o n ( x - 3 )} b = - \frac{y}{o n ( x - 3 )} b = 0 b = 0

代用を戻す

m = a + bi

m = \frac{y}{o n ( x - 3 )} i, m = - \frac{y}{o n ( x - 3 )} i, m = \frac{y}{o n ( - x ^{2} + 6 x - 9 )}, m = - \frac{y}{o n ( - x ^{2} + 6 x - 9 )}