2+iy=x-2i

解答

2 + i y = x - 2 i

x = 2, y = - 2

求解步骤

2 + i y = x - 2 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[2 = x y = - 2]

[2 = x y = - 2] : x = 2, y = - 2

x = 2, y = - 2

\frac{6}{x + y i + ( 2 - i ) ^{2}} = 4 - 3 i

so l v e f or x, s i f = y x^{2} - x y^{3}

\frac{( 18 + i )}{4 + 3 i} = a + bi

in (in (in x)) = y

(1 + x) = (1 + r) \cdot (1 + i)