What are the solutions to the equation (x+1)^2-18=0 ?

The solutions to the equation (x+1)^2-18=0 are x=3sqrt(2)-1,x=-3sqrt(2)-1

Find the zeros of (x+1)^2-18=0

The zeros of (x+1)^2-18=0 are x=3sqrt(2)-1,x=-3sqrt(2)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{2} - 18 = 0

x = 32 - 1, x = - 32 - 1

Decimal Notation

x = 3.24264 \dots, x = - 5.24264 \dots

Solution steps

(x + 1)^{2} - 18 = 0

Move

18

to the right side

(x + 1)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 18 : x = 32 - 1

Solve

x + 1 = - 18 : x = - 32 - 1

The solutions to the quadratic equation are:

x = 32 - 1, x = - 32 - 1

x^{2} + 3 x - 10 \geq 0

(2 x + 4)^{2} = (x + 3)^{2}

9 x^{2} - 24 x + 12 = 0

(x - 1) (x + 4) = 14

2 (- 1)^{3} - 12 (- 1)^{2} - 30 (- 1) + 9

What are the solutions to the equation (x+1)^2-18=0 ?
The solutions to the equation (x+1)^2-18=0 are x=3sqrt(2)-1,x=-3sqrt(2)-1
Find the zeros of (x+1)^2-18=0
The zeros of (x+1)^2-18=0 are x=3sqrt(2)-1,x=-3sqrt(2)-1