What are the solutions to the equation 3q^2+2q=0 ?

The solutions to the equation 3q^2+2q=0 are q=0,q=-2/3

Find the zeros of 3q^2+2q=0

The zeros of 3q^2+2q=0 are q=0,q=-2/3

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3 q^{2} + 2 q = 0

q = 0, q = - \frac{2}{3}

Decimal Notation

q = 0, q = - 0.66666 \dots

Solution steps

3 q^{2} + 2 q = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

2^{2} - 4 \cdot 3 \cdot 0 = 2

q_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- 2 + 2}{2 \cdot 3}, q_{2} = \frac{- 2 - 2}{2 \cdot 3}

q = \frac{- 2 + 2}{2 \cdot 3} : 0

q = \frac{- 2 - 2}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

q = 0, q = - \frac{2}{3}

\frac{( 9 ^{- 2} )}{( 3 ^{- 3} )}

\frac{13}{15} - \frac{1}{2}

10 b - 30 a b^{2}

x + 7 = 19

23 \cdot 4

What are the solutions to the equation 3q^2+2q=0 ?
The solutions to the equation 3q^2+2q=0 are q=0,q=-2/3
Find the zeros of 3q^2+2q=0
The zeros of 3q^2+2q=0 are q=0,q=-2/3