log_{10}(x)(6x+16)=2

Lösung

lo g_{10} (x) (6 x + 16) = 2

Keine L \overset{o}{¨} sung f \overset{u}{¨} r x \in R

Schritte zur Lösung

lo g_{10} (x) (6 x + 16) = 2

Keine L \overset{o}{¨} sung f \overset{u}{¨} r x \in R

2.8 = lo g_{10} (\frac{x}{x - 100})

- 4 lo g_{3} (- 9 x) = - 4

ln (x) + x = 0.01

ln (3 x) = 1.3

so l v e f or x, ln (x) = e^{y}