log_{5}(2x)=-1

Lösung

lo g_{5} (2 x) = - 1

x = \frac{1}{10}

Dezimale

x = 0.1

Schritte zur Lösung

lo g_{5} (2 x) = - 1

Wende die log Regel an

2 x = \frac{1}{5}

Löse

2 x = \frac{1}{5} : x = \frac{1}{10}

x = \frac{1}{10}

lo g_{2} (3 x^{2} - 2 x - 1) = 5

ln (Y) = 3

so l v e f or w, q = a \cdot ln (b w + 1)

ln (Y) = 0

so l v e f or y, - ln (y + 6) = x^{2}