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受欢迎的代数 >

6.0206=-10log_{10}((1-x)^2)

解答

6.0206 = - 10 lo g_{10} ((1 - x)^{2})

解答

x = - \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1, x = \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1

+1

十进制

x = 0.50000 \dots, x = 1.49999 \dots

求解步骤

6.0206 = - 10 lo g_{10} ((1 - x)^{2})

交换两边

- 10 lo g_{10} ((1 - x)^{2}) = 6.0206

两边除以

- 10

lo g_{10} ((1 - x)^{2}) = - \frac{6.0206}{10}

使用对数运算法则

(1 - x)^{2} = \frac{1}{1 0 ^{\frac{6.0206}{10}}}

解

(1 - x)^{2} = \frac{1}{1 0 ^{\frac{6.0206}{10}}} : x = - \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1, x = \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1

x = - \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1, x = \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1

验证解:

x = - \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1

真

, x = \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1

真

解为

x = - \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1, x = \frac{1}{1 0 ^{\frac{6.0206}{10}}} + 1

作图

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