log_{3}(2x)=5

Lösung

lo g_{3} (2 x) = 5

x = \frac{243}{2}

Dezimale

x = 121.5

Schritte zur Lösung

lo g_{3} (2 x) = 5

Wende die log Regel an

2 x = 243

Löse

2 x = 243 : x = \frac{243}{2}

x = \frac{243}{2}

4.86 = - lo g_{10} (x)

z + ln (1 + z) = 0

lo g_{5} (4 x) + 1 = 2

x - 1 = ln (x)

lo g_{10} (8 v - 9) = lo g_{10} (5 v)