ln(3x+1)=5

Lösung

ln (3 x + 1) = 5

x = \frac{e ^{5} - 1}{3}

Dezimale

x = 49.13771 \dots

Schritte zur Lösung

ln (3 x + 1) = 5

Wende die log Regel an

3 x + 1 = e^{5}

Löse

3 x + 1 = e^{5} : x = \frac{e ^{5} - 1}{3}

x = \frac{e ^{5} - 1}{3}

so l v e f or X, ln (2 X) = Y

lo g_{2} (lo g_{x} (16)) = 3

lo g_{4} (x - 3) + lo g_{4} (x) = 1

lo g_{4} (x) + 4 = 9

3 - ln (x) = 2