1=|d-40|

Lösung

1 = ∣ d - 40 ∣

d = 39 or d = 41

Schritte zur Lösung

1 = ∣ d - 40 ∣

Tausche die Seiten

∣ d - 40 ∣ = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

d - 40 = - 1 or d - 40 = 1

d - 40 = - 1 or d - 40 = 1

d = 39 or d = 41

so l v e f or u, ∣ u + v ∣ = 2

x^{2} - 6 x + 5 = 2 x - 2

2 ∣ 4 n - 16 ∣ = 0

∣ d ∣ - 5 = 13

\frac{2 x - 3}{5} = 9