|x^2+10x|=25

Lösung

x^{2} + 10 x = 25

x = - 5 (1 + 2) or x = - 5 or x = 5 (2 - 1)

Dezimale

x = - 12.07106 \dots, x = - 5, x = 2.07106 \dots

Schritte zur Lösung

x^{2} + 10 x = 25

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 10 x = - 25 or x^{2} + 10 x = 25

x^{2} + 10 x = - 25 or x^{2} + 10 x = 25

x = - 5 or (x = - 5 (1 + 2) or x = 5 (2 - 1))

x = - 5 (1 + 2) or x = - 5 or x = 5 (2 - 1)

∣ x ∣ + 14 = 23

\frac{∣ 5 + 9 x ∣}{10} = 5

x^{2} - 6 = 6 + x

∣ 2 x + 5 ∣ - 7 = 4

- 8 ∣ a - 9 ∣ - 10 = - 114