What are the solutions to the equation -x^2+120=0 ?

The solutions to the equation -x^2+120=0 are x=2sqrt(30),x=-2sqrt(30)

Find the zeros of -x^2+120=0

The zeros of -x^2+120=0 are x=2sqrt(30),x=-2sqrt(30)

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- x^{2} + 120 = 0

x = 230, x = - 230

Decimal Notation

x = 10.95445 \dots, x = - 10.95445 \dots

Solution steps

- x^{2} + 120 = 0

Move

120

to the right side

- x^{2} = - 120

Divide both sides by

- 1

x^{2} = 120

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 120, x = - 120

120 = 230

- 120 = - 230

x = 230, x = - 230

7 m + 11 - 5 m - 2 = 2 m - 9

11 \geq y + 10

\frac{6 - 7 i}{3 i}

4 x^{2} = 80

What are the solutions to the equation -x^2+120=0 ?
The solutions to the equation -x^2+120=0 are x=2sqrt(30),x=-2sqrt(30)
Find the zeros of -x^2+120=0
The zeros of -x^2+120=0 are x=2sqrt(30),x=-2sqrt(30)