What are the solutions to the equation x^2-7x-12=0 ?

The solutions to the equation x^2-7x-12=0 are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2

Find the zeros of x^2-7x-12=0

The zeros of x^2-7x-12=0 are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 7 x - 12 = 0

x = \frac{7 + 97}{2}, x = \frac{7 - 97}{2}

Decimal Notation

x = 8.42442 \dots, x = - 1.42442 \dots

Solution steps

x^{2} - 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 12) = 97

x_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 1}

x = \frac{- ( - 7 ) + 97}{2 \cdot 1} : \frac{7 + 97}{2}

x = \frac{- ( - 7 ) - 97}{2 \cdot 1} : \frac{7 - 97}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 97}{2}, x = \frac{7 - 97}{2}

2 - \frac{3}{4}

\frac{d}{4} = 10

3 c + 9 5 d

\frac{x + 1}{2} + \frac{5 + x}{6} = 1 + \frac{9 - 2 x}{3}

\frac{3 x}{5} + \frac{x}{9} = - 1

What are the solutions to the equation x^2-7x-12=0 ?
The solutions to the equation x^2-7x-12=0 are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2
Find the zeros of x^2-7x-12=0
The zeros of x^2-7x-12=0 are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2