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Beliebt Algebra >

10(4x^3-15x^2+16x-4)=0

Lösung

10 (4 x^{3} - 15 x^{2} + 16 x - 4) = 0

Lösung

x = 2, x = \frac{7 + 17}{8}, x = \frac{7 - 17}{8}

+1

Dezimale

x = 2, x = 1.39038 \dots, x = 0.35961 \dots

Schritte zur Lösung

10 (4 x^{3} - 15 x^{2} + 16 x - 4) = 0

Faktorisiere

10 (4 x^{3} - 15 x^{2} + 16 x - 4) : 10 (x - 2) (4 x^{2} - 7 x + 2)

10 (x - 2) (4 x^{2} - 7 x + 2) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x - 2 = 0 or 4 x^{2} - 7 x + 2 = 0

Löse

x - 2 = 0 : x = 2

Löse

4 x^{2} - 7 x + 2 = 0 : x = \frac{7 + 17}{8}, x = \frac{7 - 17}{8}

Die Lösungen sind

x = 2, x = \frac{7 + 17}{8}, x = \frac{7 - 17}{8}

Graph

Beliebte Beispiele

k^{3} - 3 k^{2} + k + 2 = 0

5=3x^3+4x^2+6x+5

5 = 3 x^{3} + 4 x^{2} + 6 x + 5

(2x-1)^6=(2x-1)^8

(2 x - 1)^{6} = (2 x - 1)^{8}

C^8=(ln(7)+C)/7

C^{8} = \frac{ln ( 7 ) + C}{7}

2 x^{4} - x^{3} + x + 2 = 0