faktorisieren 1/512 x^9-512

Lösung

faktorisieren

\frac{1}{512} x^{9} - 512

(\frac{x}{2} - 2) (\frac{x ^{2}}{4} + x + 4) (\frac{x ^{6}}{64} + x^{3} + 64)

Schritte zur Lösung

\frac{1}{512} x^{9} - 512

Faktorisiere

\frac{x ^{9}}{512} - 512 : (\frac{x}{2} - 2) ((\frac{1}{2})^{2} x^{2} + x + 2^{2}) ((\frac{1}{8})^{2} x^{6} + x^{3} + 8^{2})

= (\frac{x}{2} - 2) ((\frac{1}{2})^{2} x^{2} + x + 2^{2}) ((\frac{1}{8})^{2} x^{6} + x^{3} + 8^{2})

Vereinfache

(\frac{x}{2} - 2) ((\frac{1}{2})^{2} x^{2} + x + 2^{2}) ((\frac{1}{8})^{2} x^{6} + x^{3} + 8^{2}) : (\frac{x}{2} - 2) (\frac{x ^{2}}{4} + x + 4) (\frac{x ^{6}}{64} + x^{3} + 64)

= (\frac{x}{2} - 2) (\frac{x ^{2}}{4} + x + 4) (\frac{x ^{6}}{64} + x^{3} + 64)

f a c t or 2 x - 6

- 12 x - 8 \leq 64

- 6 = C e^{\frac{1}{10}}

4 x^{2} + 16 x + 15 = 0

x^{2} + 7 x = - 10