x^2<= 64

The solution to x^2<= 64 is -8<= x<= 8

Solution

x^{2} \leq 64

- 8 \leq x \leq 8

Interval Notation

[- 8, 8]

Solution steps

x^{2} \leq 64

For

u^{n} \leq a

, if

n

is even then

- 64 \leq x \leq 64

64 = 8

- 8 \leq x \leq 8

\frac{4}{52} \cdot \frac{3}{51} \cdot \frac{2}{50} \cdot \frac{1}{49}

\frac{k ( k + 1 ) ( 2 k + 1 )}{6} + (k + 1)^{2}

- \frac{2}{5} - \frac{4}{5} + (- \frac{9}{10})

- 1 < x < 6

- (\frac{5}{3})^{4}