20000=17100*(1+x)^3

Lösung

20000 = 17100 \cdot (1 + x)^{3}

x = \frac{2 3 25}{3 171} - 1, x = (- 3 \frac{25}{171} - 1) + i \frac{17 1 ^{\frac{2}{3}} 3 25 3}{171}, x = (- 3 \frac{25}{171} - 1) - i \frac{17 1 ^{\frac{2}{3}} 3 25 3}{171}

Schritte zur Lösung

20000 = 17100 (1 + x)^{3}

Tausche die Seiten

17100 (1 + x)^{3} = 20000

Teile beide Seiten durch

17100

(1 + x)^{3} = \frac{200}{171}

Für

g^{3} (x) = f (a)

sind die Lösungen

g (x) = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

Löse

1 + x = 3 \frac{200}{171} : x = \frac{2 3 25}{3 171} - 1

Löse

1 + x = 3 \frac{200}{171} \frac{- 1 + 3 i}{2} : x = (- 3 \frac{25}{171} - 1) + i \frac{17 1 ^{\frac{2}{3}} 3 25 3}{171}

Löse

1 + x = 3 \frac{200}{171} \frac{- 1 - 3 i}{2} : x = (- 3 \frac{25}{171} - 1) - i \frac{17 1 ^{\frac{2}{3}} 3 25 3}{171}

Die Lösungen sind

x = \frac{2 3 25}{3 171} - 1, x = (- 3 \frac{25}{171} - 1) + i \frac{17 1 ^{\frac{2}{3}} 3 25 3}{171}, x = (- 3 \frac{25}{171} - 1) - i \frac{17 1 ^{\frac{2}{3}} 3 25 3}{171}

x^{4} - 6 x - 4 = 0

8 x^{6} + 9 x^{3} + 1 = 0

2 x^{4} - 11 x^{2} + 5 = 0

[(x) \cdot x^{3} + 4 - 7] = 24

94 = b^{3}