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Beliebt Algebra >

-x(x^2-1)(x^2+4)=0

Lösung

- x (x^{2} - 1) (x^{2} + 4) = 0

Lösung

x = 0, x = - 1, x = 1, x = 2 i, x = - 2 i

Schritte zur Lösung

- x (x^{2} - 1) (x^{2} + 4) = 0

Faktorisiere

- x (x^{2} - 1) (x^{2} + 4) : - x (x + 1) (x - 1) (x^{2} + 4)

- x (x + 1) (x - 1) (x^{2} + 4) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x = 0 or x + 1 = 0 or x - 1 = 0 or x^{2} + 4 = 0

Löse

x + 1 = 0 : x = - 1

Löse

x - 1 = 0 : x = 1

Löse

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

Die Lösungen sind

x = 0, x = - 1, x = 1, x = 2 i, x = - 2 i

Graph

Beliebte Beispiele

x^{5} - 3 x + 1 = 0

-2(9x^2-49)(x^2-5)=0

- 2 (9 x^{2} - 49) (x^{2} - 5) = 0

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x^{4} - 7 x^{3} + 12 x^{2} + 4 x - 16 = 0

-9x^4-46x^2+5=0

- 9 x^{4} - 46 x^{2} + 5 = 0

2 x^{3} + 1 = x^{2} + 2 x