2^{2x+15}=3^{x-40}

Lösung

2^{2 x + 15} = 3^{x - 40}

x = \frac{- 40 ln ( 3 ) - 15 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

Dezimale

x = - 188.89497 \dots

Schritte zur Lösung

2^{2 x + 15} = 3^{x - 40}

Wende Exponentenregel an

(2 x + 15) ln (2) = (x - 40) ln (3)

Löse

(2 x + 15) ln (2) = (x - 40) ln (3) : x = \frac{- 40 ln ( 3 ) - 15 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{- 40 ln ( 3 ) - 15 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

7^{y} = 14

4 1 6^{x + 5} = 4^{x + 3}

5^{x} = 3^{2 x + 1}

7^{2 x + 5} = 5 \cdot (3^{3 x})

2^{x} = \frac{4 ^{x - 2}}{8}