400e^{-3k}=2000e^{-10k}

Lösung

400 e^{- 3 k} = 2000 e^{- 10 k}

k = \frac{ln ( 5 )}{7}

Dezimale

k = 0.22991 \dots

Schritte zur Lösung

400 e^{- 3 k} = 2000 e^{- 10 k}

Wende Exponentenregel an

ln (400) - 3 k = ln (2000) - 10 k

Löse

ln (400) - 3 k = ln (2000) - 10 k : k = \frac{ln ( 5 )}{7}

k = \frac{ln ( 5 )}{7}

5^{x} = 100000

so l v e f or t, e^{k t} = \frac{1}{3}

1.0 5^{n} = 2

so l v e f or y, x = e^{5 (y - 9)}

4 9^{x} + 1 = 2 (7^{x})