2^x=3^{1-x}

Lösung

2^{x} = 3^{1 - x}

x = \frac{ln ( 3 )}{ln ( 6 )}

Dezimale

x = 0.61314 \dots

Schritte zur Lösung

2^{x} = 3^{1 - x}

Wende Exponentenregel an

x ln (2) = (1 - x) ln (3)

Löse

x ln (2) = (1 - x) ln (3) : x = \frac{ln ( 3 )}{ln ( 6 )}

x = \frac{ln ( 3 )}{ln ( 6 )}

5 = 10 e^{- 0.008 (x)}

3^{x} - 3^{x - 2} = a \cdot 3^{x}

e^{2 b} = b + 3

500000 = - 3 e^{- 5 x} + 35.156

7 5^{x} = 25