25^{x+2}=5^{x^2+6x+7}

Lösung

2 5^{x + 2} = 5^{x^{2} + 6 x + 7}

x = - 1, x = - 3

Schritte zur Lösung

2 5^{x + 2} = 5^{x^{2} + 6 x + 7}

Wende Exponentenregel an

2 (x + 2) = x^{2} + 6 x + 7

Löse

2 (x + 2) = x^{2} + 6 x + 7 : x = - 1, x = - 3

x = - 1, x = - 3

4^{x} - 2^{x} = 2

5^{2 x - 3} = 7^{x - 1}

ln (e^{5 x}) + ln (4) = 6

e^{2 x} - 11 e^{x} + 28 = 0

4^{x + 2} = 8^{- 2 x}