-y^2+y+6=0

解

- y^{2} + y + 6 = 0

y = - 2, y = 3

解答ステップ

- y^{2} + y + 6 = 0

解くとthe二次式

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 6 = 5

y_{1, 2} = \frac{- 1 \pm 5}{2 ( - 1 )}

解を分離する

y_{1} = \frac{- 1 + 5}{2 ( - 1 )}, y_{2} = \frac{- 1 - 5}{2 ( - 1 )}

y = \frac{- 1 + 5}{2 ( - 1 )} : - 2

y = \frac{- 1 - 5}{2 ( - 1 )} : 3

二次equationの解:

y = - 2, y = 3