2^{4x-1}=3^x

Lösung

2^{4 x - 1} = 3^{x}

x = \frac{ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

Dezimale

x = 0.41407 \dots

Schritte zur Lösung

2^{4 x - 1} = 3^{x}

Wende Exponentenregel an

(4 x - 1) ln (2) = x ln (3)

Löse

(4 x - 1) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

3 = 8 (2)^{5 x} - 15

32 = 1 6^{x + 4}

81 = 3 3^{x}

4^{- x} = 256

e^{t} = 687