What are the solutions to the equation 3x^2-15x+11=-2x+2 ?

The solutions to the equation 3x^2-15x+11=-2x+2 are x=(13+sqrt(61))/6 ,x=(13-sqrt(61))/6

Find the zeros of 3x^2-15x+11=-2x+2

The zeros of 3x^2-15x+11=-2x+2 are x=(13+sqrt(61))/6 ,x=(13-sqrt(61))/6

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3 x^{2} - 15 x + 11 = - 2 x + 2

x = \frac{13 + 61}{6}, x = \frac{13 - 61}{6}

Decimal Notation

x = 3.46837 \dots, x = 0.86495 \dots

Solution steps

3 x^{2} - 15 x + 11 = - 2 x + 2

Move

2

to the left side

3 x^{2} - 15 x + 9 = - 2 x

Move

2 x

to the left side

3 x^{2} - 13 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

(- 13)^{2} - 4 \cdot 3 \cdot 9 = 61

x_{1, 2} = \frac{- ( - 13 ) \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 61}{2 \cdot 3}, x_{2} = \frac{- ( - 13 ) - 61}{2 \cdot 3}

x = \frac{- ( - 13 ) + 61}{2 \cdot 3} : \frac{13 + 61}{6}

x = \frac{- ( - 13 ) - 61}{2 \cdot 3} : \frac{13 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{13 + 61}{6}, x = \frac{13 - 61}{6}

x^{2} + 2 x = 48

\frac{7 ^{6}}{7 ^{- 2}}

x^{2} = 6 x - 19

10 x^{2} - 29 x - 3

49 x^{2} - 36 y^{2}

What are the solutions to the equation 3x^2-15x+11=-2x+2 ?
The solutions to the equation 3x^2-15x+11=-2x+2 are x=(13+sqrt(61))/6 ,x=(13-sqrt(61))/6
Find the zeros of 3x^2-15x+11=-2x+2
The zeros of 3x^2-15x+11=-2x+2 are x=(13+sqrt(61))/6 ,x=(13-sqrt(61))/6